V2EX = way to explore
V2EX 是一个关于分享和探索的地方
Sign Up Now
For Existing Member Sign In
推荐学习书目
› Learn Python the Hard Way
Python Sites
› PyPI - Python Package Index
› http://diveintopython.org/toc/index.html
› Pocoo
值得关注的项目
› PyPy
› Celery
› Jinja2
› Read the Docs
› gevent
› pyenv
› virtualenv
› Stackless Python
› Beautiful Soup
› 结巴中文分词
› Green Unicorn
› Sentry
› Shovel
› Pyflakes
› pytest
Python 编程
› pep8 Checker
Styles
› PEP 8
› Google Python Style Guide
› Code Style from The Hitchhiker's Guide
This topic created in 4038 days ago, the information mentioned may be changed or developed.
我想爬取某一个网页，一个div下的每一条a，但是第一条是标题，而且和剩下的结构不同，会造成如下错误：
我的想法是爬取的内容应该为：
{“省”：["a","b","c"],“市”:["d","e","f"],“区”：["g","h","i"]},但会变成：
{"省"：["a","b","c"],“市”:["d","e","f"],“区”：["地区"，"g"，"h"]
应该怎么办，我如何从第二条开始爬取。我本想在定义sites时改为 //div/a[2], 但是不成功。
scrapy新手求助！！！
我的想法是爬取的内容应该为：
{“省”：["a","b","c"],“市”:["d","e","f"],“区”：["g","h","i"]},但会变成：
{"省"：["a","b","c"],“市”:["d","e","f"],“区”：["地区"，"g"，"h"]
应该怎么办，我如何从第二条开始爬取。我本想在定义sites时改为 //div/a[2], 但是不成功。
scrapy新手求助！！！
 |
1
Septembers Apr 7, 2015 via Android
没样本这不是扯淡么？
|
 |
2
willdatascience OP @Septembers 额。要是能截图我就发html了。。
|
|
3
Septembers Apr 7, 2015 via Android
@willdatascience gist
|
 |
4
aaaa007cn Apr 7, 2015
//div/a[position()>1]
//div/a/following-sibling::a |
 |
5
zjuster Apr 7, 2015
//div/a[2] 是只抽取第二个a结点，试试/a[position()>1]，
常用的xpath配置到w3school看看，都有。 |
 |
6
oseau Apr 7, 2015
|
Select Language