关于 ThreadPoolExecutor 的问题

Code：
--------------------------------------------------------------
import time
from concurrent.futures import ThreadPoolExecutor

def work_01(i):
time.sleep(1)
print(i)

def work_02(i):
time.sleep(2)
print(i)

def work_03(i):
time.sleep(3)
print(i)

with ThreadPoolExecutor(max_workers=5) as executor:
for i in range(2):
executor.submit(work_01, i)
executor.submit(work_02, i)
executor.submit(work_03, i)

print('over')
-------------------------------------------------------------------

return：
-------------------------------------------------------------------
0
1
0
1
0
1
over
-------------------------------------------------------------------

question:
-------------------------------------------------------------------
1. 在这里提问题怎么上传图片呀？
2. executor.submit(work_01, i) executor.submit(work_02, i) executor.submit(work_03, i)
这三个任务是需要依次顺序执行的，仅在三个任务顺序执行完再一次性打印结果，这有
点类似于 mysql 的组合唯一值，同时我的线程池也是生效的，不会等待 3 个任务执行完再
执行下 3 个任务
3. 理想的展示效果如下：
0
0
0
1
1
1
over

或

1
1
1
0
0
0
over
-------------------------------------------------------------------

Executor

submit

work_01

6 条回复 • 2018-07-28 08:53:07 +08:00