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这是一个创建于 1291 天前的主题，其中的信息可能已经有所发展或是发生改变。
class Meta(type):
def __new__(self,class_name,bases,attrs):
print(attrs)
return type(class_name,bases,attrs)
Meta('dog',(),{'x':5})
输出：{'x': 5}
class Meta(type):
def __new__(self,class_name,bases,attrs):
print(attrs)
return type(class_name,bases,attrs)
class Dog(metaclass = Meta):
x = 5
输出：{'__module__': '__main__', '__qualname__': 'Dog', 'x': 5}
请问两者是类似 class name:和 type(name,(),{})的这种等价吗...
def __new__(self,class_name,bases,attrs):
print(attrs)
return type(class_name,bases,attrs)
Meta('dog',(),{'x':5})
输出：{'x': 5}
class Meta(type):
def __new__(self,class_name,bases,attrs):
print(attrs)
return type(class_name,bases,attrs)
class Dog(metaclass = Meta):
x = 5
输出：{'__module__': '__main__', '__qualname__': 'Dog', 'x': 5}
请问两者是类似 class name:和 type(name,(),{})的这种等价吗...
1 条回复 • 2021-06-13 13:59:39 +08:00
 |
1
NKID00 2021-06-13 13:59:39 +08:00  1
class name: 和 type(name, (), {}) 在某些特殊情况下不一定等价
https://gist.github.com/NKID00/51021e03c8f979df5bf4cb5adca64cc7 |
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